0=25x^2+50x

Solution for 0=25x^2+50x equation:

0=25x^2+50x

We move all terms to the left:

0-(25x^2+50x)=0

We add all the numbers together, and all the variables

-(25x^2+50x)=0

We get rid of parentheses

-25x^2-50x=0

a = -25; b = -50; c = 0;
Δ = b2-4ac
Δ = -502-4·(-25)·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50}{2*-25}=\frac{0}{-50}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50}{2*-25}=\frac{100}{-50}
=-2
$